PlanetZ forums - scopeusers.com

<a name="planetz-file"></a><a href="http://www.planetz.com/Pulsar/files/mod ... .dev"><img src="/forums/images/file_icon.gif" border="0" alt=" File"> File</a><BR> <a name="planetz-tag"></a>Type: Mixer<BR> <a name="planetz-tag"></a>Pulsar Version: SFP 3.1<BR> <a name="planetz-tag"></a>Requires: Modular 3<BR> _____________________________________<BR><BR> here's what michu suggested to do, rodos - works well.

this thread explains this patch.

<font size=-1>[ This Message was edited by: wayne on 2004-05-27 11:55 ]</font><BR><BR><a name="planetz-fileimage"></a><IMG SRC="http://www.planetz.com/Pulsar/files/mod ... dosmix.bmp" BORDER="0">

Thank you SO much both of you guys for your valuable help!

a truly global effort!

Is this an amazing forum or what?

/d

..and an amazing technology...

Hello my friends!

A global effort, an amazing forum and an amazing technology indeed! I ve got a small problem and I ve got a question as well.

The problem is that I am missing OBXFLX.DSP file. Is that a Flexor Module (Half Inverter)? Because I dont have it...

Anyway, as I am a real novice in synths in general, I d like you to explain me a bit the module, so that I can start learning and understanding a bit!

I quote Michu's original idea:

On 2004-05-27 10:47, Michu wrote:
of the top of my head
A = const. value bipolar > half wave rectifier
B = const. val. bipolar > full wave rectifier > half inverter
C = const. value bipolar > inverter > half wave rectifier

So, lets say that I give a constant value equal to -64.
A: -64 (passing through a half-rectifying diode) makes it a 0. So signal A is not present
B: -64 (passing through a full-wave rectifying diode) makes it a 64. But what can a half inverter do to a value? A half inverter would shift something by 90 degrees, right? I dont get how a value can be shifted... Or does it mean that it will be divided by 2? So, resulting 32?
C: -64 (passing through an inverter) makes it 64, right??

So, for a value of -64 I got 0,32,64
For a value of 0 I get 0, ?, 0
And for a value of 64 I get 64, 32, -64...

It doesnt make any sense to me... Could you please enlighten me a bit?

Thank you very much!

<font size=-1>[ This Message was edited by: rodos1979 on 2004-05-28 21:54 ]</font>

mmm...I thought that I could make a circle with the values: -64 0 64 0 and back to the begining. So a half inverter would mean to go a step to the right and an inverter 2 steps to the right (change of +- signal).
So the values I get are:
For -64, the values are 0, 0, 64
For 0, the values are 0, 64, 0
For 64, the values are 64, 0, 0

Is that right?

Michu, you are a genious!

aah, so sorry rodos, half inverter is flexor

here's the readme on half inverter:-

"This module is useful when dealing with unipolar signals such as envelopes and constant values. It inverts only the positive range of an incoming signal,so a value of 0 amplitude becomes 1(maximum amplitude) and a value of 1 becomes 0 (minimum amplitude). It is ideal for creation of inverted envelopes and other unipolar control signals."

your calculations are correct, and it's probably time to get flexor

you will love it just for the filters.

It sort of seems a strange thing for us more traditional instrumentalists to buy, but i think in the future every musician will have something like this in their setup, for spontaneous creation of tools & instruments.

another thing, this machine crackles a little bit when sliding the constant value too quickly - this is fixed with some control smoother (flexor) between the constant value and the rectifiers/inverter.
maybe i'll re-upload it.